ENGR 225 HW2 solutions-1_1

ENGR 225 HW2 solutions-1_1 - @113th 2 . L01 Pm anrtsnS'we...

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Unformatted text preview: @113th 2 . L01 Pm anrtsnS'we proper“ IS dapemdewl" on Jrhg amt-NM 0%; a Subgfimee or ’éxfi'vfir 0*? 2L qufim\ Mum 2m inJrenENe (ampef+\{ Is ‘andependevfi Oi; amomfi QC micanlr. E xk-enswe Iw‘t-ans‘x we; B WA?“ d9 (“mum W 93% Indep emde‘rfi' % UPQQ( C039. 1€+JFGJFS USU E‘uq \Owgvcag‘a li+1rer3 3 can be cmweflrw Jm 9 based on mass (5? -l-'ma am \n-‘rexns‘me, Pmpamki \ml ~ number a? - , w + dimdmg ‘Dx! Jane may; moles pfasm L” mass and numer 0’? (Woks CP 3 CV 1 P} T} and (a 31W 34%ch (LSH’QRSNQ are a“ shieer inflns‘we a wars in [mi ox’j}e%c. 3% UhH—S in pru- kc) er Per km: Moire: Them mag he. answers oHner Hum 44/1330. 5, WW D Equajdmn arr saw, :- J; (P1 uj) =0 '5 pressure} 1) 2 specific; \Jc\ume) T; Jmmpewmhm Q Cv\br1§}ic ectuaidews 0-? SJwA-e: ‘— ’ 9“ " + aner~ 9"}.(UW ‘3‘}? :0 [A : spaukc m Una (EH J‘ZEUM-fip'} :Q ht. 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Pl} = N2“ - M. an . 3 N -.: W 1‘ \{S‘m‘fi unfit) ‘ Cm 2450 Ca‘xcuh’re we “1 mwfihflmfi' m (1% K“) and make mbfieruaéfi an N - Hohmowz {€3.93qu : 'Dfiaqgk NH? .\~..W‘“”‘*\ does “6+ WW, wx Np; : H0032 UL)“ PI: (0.673 «33 2 0-00‘4‘3 ‘Lm é SU‘OS-kahae. gamrfiulgmflw—‘E 051‘le W Hm: MIMNL‘: 0.03% km [73.6% $39 = \O.£36‘1 kgl MHz: NHE’WIHa = {JAIN-1% kw: (mom fig 2 \a.oxq% Q I mm mm”: MW mgwm fie : sm‘ms kai U? }_ LU LU I m D U} ‘_ 'd..' .u E 2” C: D #- (\' u: f... m w I m a. c: H I"; ‘7 22-141 I"! a m mil-:1: ...;-) Wflfl. P‘\ T:’3lC}-1 lU-"2_.7_,Ci33 *E/kj 1P5? me: “name 1),]: {M 5WD WK ‘P: [95,“. (3191;): 6.1311 Mai L: L; + x 06 FH4\ =-:sv,374- cesvin)(1$£7.m.:s%37) 11; [W35: on +6 as) C} T‘Zlck’ PIIDFfi } 0:2 m'E mm; ‘D,{ g P a firm Carola) V‘ru‘; (T: EM—B —’ V"; (East) : ,CIHDC’G? n-EHCj \1‘7 .oomotn 4-3/9 I T534535, Fi‘irf’fi :H:? has ch' DJ. : 19L FMT (3191‘) ‘5 mm VApom we MST“ 'Dfoé m— !amm was D’s l bf" 1311.5? NHL) 253.4473 H25 "um. - ;"‘-; 22-141 22-144 I? 41754 F? ' i?” J GEM g\ T 5 697.0%. k.) F7; 11.0“; 3.19.3} U: WLE "DJ 4) 05 .DoilsS‘Q raj/Jag i T: GQ‘OK‘ 431—? “?fi ) fr? 1% m ~» We N‘s-1’ mmhse 1 F: 63,131 1:; [~13 i ! lb) Tra‘C-‘DKJ P: S‘L‘Ffi ,5:? | l WLE "0.1. -'> 5U‘Pazfi'c-W vwm. 'P—Eblfid WE N'STDWsE S S: mos-'7: 14' hawk PROBLEM 2.87 KNOWN: P, = Mo we Pl: Mo wq ______... T‘ = ‘75 °C TL = 850%. Fmo: v, M, 0,5, NM Ill-24:0,.) Fae fiTATES I Am: 2, A55UMPno~sz STEAD‘f—STATE 09514TION. Aways: FrLoM NIST DATABASE" IN LE‘T Ou-r LET 3 u -; 0.00f0353 “3/3 U: 0.074337 m/kj 1”: 403.20; I‘I/lcj In: 4250.5 MA? u = 3%.” 5/5 u: 3737.1 I"3/ch s : 1.2+53 "T4344 5: 7.70:3 “913% REGION: Llath (COMPRESJED) Ramon: VAPOR. (SUPERHEATEO) COMMENTS: WHILE 11-115 DAV. wouw TAKE JOME "nus: Tb IJTEILPOLAI'E' __________. Fund {mem'w TABLES’ IT our [5; Foul/00 Fnam NIST w A MAT-rat 0F screws. m= 2.7 kg \JQ : \j : m3 .:_ 7. P : WOO ‘V—Pa VV __ 7: WM =3 V 0.5Lalam3 V :— m w: 2.1.“.5 F 0.1M) W\3{p_% Kr Tabb Elk VI: = 0.0mm M‘ixcg V93 "— (3.11171 m3(\,._% V—V; (30.10 I o.oouo<5,_rfl : 2 .__#————fl : X v5"\.1f m3 O .1111”! " 0.0{3HOE 1% >4:— ‘TPU ‘uapof 0‘? 4:an m‘wfimfi‘i \IV = Vsmu: (3.1111? g; (1.0% Lash 1\O.666 mg l..>< ; 370 (Lia-Luld 04} ~Hne m‘nxlrure me 3 0—K} m : (\-0.‘1\a?:\3(1-“l k5} Zkfi‘DJo'lLo m5 '3 ~ W : uflml -« moouan—S (0.La1Lu%'—5\‘:\(DFH><10"L‘ m3 I _______m_ £90546) (Sb/041% U509 “ML C’WKWJL @U’filwfi 6w aw ; We got” Qs+&’\_ Cacfiwwékc 7 v Famr—H) flu wrap/5 mgméjoc W w W551er W5 War/72: «aw/um) ’ PROBLEM 1H2. ' 7,— flm’mgfégfl 6L 6 . KNOWN: M: 0.56 1:3 ":0 mp = I134 It} CWKJCJ W _ 2 T = 50°C \\ “T. : V! = 0.0.3 r13 a 9mm AREA = A? [Ufa-u“ ’4 {39m DOWNS)“; = 10!.325 Ha '5 PFSTUM nasu ON 516?: mrrmwr Fat-n .. fl 1 3 - 114 Is Emma? 15 Anna: Un‘nL HID Is A “roman-ea v.4?“ FIND: A: Pm‘r THE mates: ON A T-v swarm”, B.- TEMPERAVURE wmm Pam» LIFTS OFF SHE’S. Pu tn Swarm: c M STOPS tuamox . ASSummons: wswns NEE 5mm; AND no No? AFFECT AREA or: w:me ‘PEKFRT‘ PISTON-WAtL SEAL! No MAS} LOST ‘ENEM'I LS ADDED Swww (Pssuno'aawusmum) 0.0 3 ANALYSiS: V,= “3-3” = 0.22! sATunATs-zo Mlxruuc M 0.134. 0.27.! = acetonftax) 1‘21 T, P chLEME. 6m 915709! $174": FMED. 2—3: mm»: RISES A5 AonmoNAL ENERG‘I IS AOOEO, wmua T AND P RemAIN ‘COnJSTAN'l‘. CONTINUED = M PROBLEM 2, NZ (cow-rmusp) W . FED or- nsnn: WHEN Puma mm; on: 5701’s) sz: "‘5 P m A » 71$ 1 “t ‘9 ~55—mtwu%)+rom3=ca x P = “‘3 + Pat-H (A9)“ PM?) A? ‘+=L0309 Mm ! I // ; C¢MMEm~sz THE CALEULA'DONJ Camp :31: smmsuzo summ 5v Frmwm PM“ nun WEN Abpma Pqt... Tb F'be P- ‘ID %ofl&;27; aiwm m MIST: “R462 0: 454.55% 07? flfije Q MWW ,9 am) WWW/9L T: 463.ng + 235,8?MU/5’7JiK-46'3‘03K) 2 LfffiffilK " ' V g I" y ' ‘ 1 ' : V. («MW OR 98511 D» ( ‘_ sa-f:%?re$ 4?) W H. 830? ~— OHSQQO‘HMRL , afgk - L/5’0 A T : EM’OK +(z.o%13’q mamao‘fim’g :‘iifiLEELE ...
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ENGR 225 HW2 solutions-1_1 - @113th 2 . L01 Pm anrtsnS'we...

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