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Physics 101 Test 3 Fall 2002

Physics 101 Test 3 Fall 2002 - [1 A lfifl-kg child is...

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Unformatted text preview: [1] A lfifl-kg child is sitting on a playground teeter—totter, 1.50 m from the pivot. What force, applied 0.300 m on the other side of the ,Ipimt1 is needed to make the child lift ofi' the ground? [.1] 3.311 s [s] 311.4 N [C] 13.3 N [D] 111 .s @133 N [2] .11 5110-111 radius play-ground merryugoaround with a moment of inertia 2000 lrgon2 is rotating freeiy with an angular speed of 1.0 radfs. Two people, each having a mass of 60 kg, are standing right outside the edge of the merry-pruned and step on with negligible speed. “rile-.1 hi the angular Speed of the mem-gmround right after the; two people have stepped on? @1110 radf's [3; 3.53 ado [e] 11.31 radfs [u] use rattle [E] 1.11 rel/s [3] The mass of Pluto is 1.20 x 1033 kg audits radius is 1.15 x 105 111. 11150111.! is the value ofg at the surface of Pluto? 0.651 171,731 [Bf1AG refs2 [C] 3.1"? mfeii [DJ 5.33133}?z [E] 3.81 111;"‘5g [41 Era-11115 tfflmpletes one resolution about its own axis every 11.24 hours. What is the radius of the orbit required for a satellite in reimlve about Uranus with the same period? Uranus has a mass 013.69 x 1025 kg. [11: 1.45 x 10“ 1:11 @321 x 10-Ir m [C] 11.03 X 101' m [D] 2.55 X it]Ii m [E] 3.41 3-: 111a 11:1 l5.- Fifid the minimum kinetic energj-r needed for a 251,000-113 rocket to escape the earth. The mass of the Earth is 5.93 >1 10“ kg, and its radius is 5.37 x [0'1 :11. [115.51 x 131:1 £319.13 x 13” 1 @1.32 21:10‘2 J [1113.31 x 101* 3 [1111.31 :1 In“ .1 [5| “711151: a mass of 0.350 kg is attached to a vertical spring and towered sterilityj the spring stretches to 12.0 cm. The mass is now distilaced from its equilibrium position and undergoes simple harmonic oscillations. What is the period of the oscillations? lAI 0.0?69 3 [Bi {1.233 3 .11.:393 a lo] 1.1.4 5 [s] 2.33 s W A Christmas ornament made from a this hollow glass sphere hangs from a small 11001: at itfi sulfate. It is observed to oscillate with a frequency of 2.50 Elie. What is the radius of the ornament? The moment Ofisertia of a hollow sphere of mass M and radius R. about a point on its edge is gM’R‘. [11] use cm [3} 0.112 cm [C] 1.341131 @2.39 am Is] 3.93 cm [3] The vertical displacement of a string is given by y(::,t] = (£1.00 mmjcosflflflfi In“): — (7.22. 3—1}1‘.]. “that is the speed of propagation of the wave? 1.1! 11.433 mfg |11] 1111 nus .222 refs [11] 3.13 mjs [at 5.3-1 rugs it}. A 13- tube. is open to the atmosphere at both otldfi. Water is primed tutu the tube- Llhtil the water rises part-way along the straight sides, and then some oil with a density 01' E120 lrgfu‘ia is poured into one end. That causes the water emface on. that side ofthe tube to go down by 5.5 mm: and the water surface on the other side to go up by the same amount. How much higher is the top surface ofthe oil on that side of the tube compared with the surface of the water on th other side of the tube? 1,151.] [1.12 11111160315 mm iC]1.E mm lD]1.1-:m [E112 em E1111: .51 spar buoy consists of a. circular cylinder, which floats with its axis oriented vertically. 011:3 Each buoy has a radius of 1.00 1:11. a height of 2.1.111 1:11 and weighs {10.0 hN. “that portion of it is submerged when it is floating in fresh water? [11] 1.13 m {11] 1.211 ru [(1] 1.35 1:11.130 m [E] 1.35 m [11; An air—tract: cart of mass m1 = 3.4!} kg an a Erintionluss horimntal air trim]: is Httachcd It: the end of a string 15121.: goes over a frictionless pullczy with a. moment of inertia. I = 8.0 x 10—5 l-zg-m2 and a radius R = 2.0 cm. The string is pqucd vettically downward by the force due to a mass m; : 0.20 kg hanging on its other and. Tutu: g 2 1H nan/s”, and find (a) the tension T1 in the string between the: cart and the Fultcm [1}] the teslsimn T3 in the string between. tin: pulley and the hanging mass, (-11) HIE magnitude :1 of the acceleration of the cart. C9 '71.: “Jr”: ”W [12] An air—track. mm. is uHucht-d to a spring and compktes one oscillation awry 5.2.5.3 5. At r. 2 H the car’r is released at a distance 01' [LEE ":1 from iis equilibrium position, in the +1 direcLimL. {it} Write an :quatiuu that describes the motion ofthe can't {namely its positinn a: as: a. function of the time I}. {M ‘What is. 1hr. IllaxiHLal velocity and acceleration of flu: cart? [fill “That is 1hr: pusitian, velociLy and acceleratian of the. can: at f- = 28.2.? 5'! T: (“2,3355 A: {main w;&l:———:f.t300'___:fluno§, (it) AzAmw—f 0’1; “New; 3:20.19“ CtI/H'frouajé) {F1 34': QLDIHCLQCEHEEE—SJ Q: ~sz cum-2‘ (C) 122,31}; wt": 43%: :wm: 51,9017 m; X = (Liam &U(%‘UDWW'):H 0 LG “'4 U': — Gym-Low? Ea, (rim-EILW! : at”) % _3_ .1. . _ . _ UL G.) x. -~-[f.uw}L(-U.LD}'§; -.-. +£13.34. s-L -__———————-—__. [13] What an airplane file-5 1:0Iianntally at an altitude Where the density of 351' is 1.20 kgfm'a and g = 9.86 mfsri‘= aha air flows with 3. Spend of 120 refs mm the upper surface of its wings; and W513]. a. speed of 11D me (War thnir boitcrm surface. {E} Find the preseum difierence between the two sides of the wings. On which side I5 51, higher? 1:13) What must be the are: of the wingfi if the total mas of the plum: '15 LEN] X 10‘: kg? (P 1 a) (emu: : “We new = @‘zEvgegu Since 1.4.1: ML (glam. Hie: 'haerfimu‘D we. ”Ir-Lumie— e‘P: T141: {g} (6”?) : L20 {In} WE'L- ‘t m L 75- [(4100 (Lo/5)] 5P *3 [-SS’xHUETpa. In) (Rewind! (Egg-Emma. Viz-Jun; ufwMCL {arm {NH—n) “Thai" mu£+ kahuna flame} umbhi.‘ APR = mg kins! ‘4 t. AWE! : “IN-E 3 Ueexlo L5) ($20 ml; ) 15F” LEE’HOS Tale A _ L “1;an -- 7i .0 w. FDRMULAE SHEET Relative velocity: T?” = LI“. + LIMI 5:” 2 ~17” Motion m. cunt—taut acceleration: 1:5 E a“ = U], ml— -..—. 1|“: Cl] 13:. = 3’3?‘ 'I'Jm=vu:+a=.l',, :1:=zn+1ii_.l, z=zu+vflfi+§c=lnl “3:1”? -2a:{:—zn) Free fall and projectile motion: 63: gfi-fln : 9.3] Huff, R = W Newton's Laws: fut = Z}: = mi. EBA = — iii-H “Eight: 13$“ 2 mglI—fl], friction: 1kinetic: f}, = .I'ikNI static: f, 5.: H,N 1' Springs: F, r —m, circular mutlun: a” : ‘H—f]: 3:], _- --—j{—1=] Work and Energy": w = Fri: Ficusfl, I1: = E‘fi )3 W = Mi, 15 = EEC =Flaj We = —.fiU| Hg = mgy, -u. = ’5: . E = K+ U. Wm = cc Impulne and Momentum: E: mfl'. I = F13: = fluff If the ::::t external impulse. ifi Hum than 117m: 2 2.17: canst Two particle collisinn: rm'fi'11+ mafigi = mlfi'” + mafzf, completely inelastic: El} :1?” Elastic collisiun: . I1"; = h}, in one dimension: vgf -- 1J- r— — 1'11—1‘fni Center of mines: 1m = int-“Hf Emh 55m = Flu-t. TWl‘F-l' F_ — 11% Rutatiunal Motion: 211' rad_ — l rev = 350*. a = w. L:- = g, m = LI:. 5: = fi‘f w=wn +r1E: .ztIzau+I'“II+“"!= fl=flg+wu£+éutz, w‘I_-wl'§+ Enffl—fla] in; .— rw‘ HEP = Irma... cl, =- Tfli, E 2: 5:11 -|- fig: rolling mat-ion: '1: '—“ II” n == I].l _ E: Rotational. kinetic energy: Km; 2 I34, I = EmirE, K: —:“1 | I‘m”— Torque: T::'4_F:rRl.=rFsinfl: TneLZETZIE=% work' W1ni —T5|'3' Angflm‘ mflmentum: L = Tpsinfl = Iw, if Tut“: = U then Lt.“ = const - _. rm 11': — I "a a: 3m. Grawty: II” ="_P1.:_1[—;-,2)1 13:36?le ”[1?“ i—,=gM, LIB :J—h“ Dficillatiuns: .1: n ficoswt, 'L‘ —' —Awsinwi, a: = —Aw3 mam! u —w=:: _ T . '.|J __ I: _ m ___ r L ‘_ a r l I f—‘Ti—aq1AWr1'l/EI. T— 211T "kl Twfififi, T—Ju‘r'gmg - -— — 3— _. ' . _ fl Waves: TJ— — — -Af y[=. t]— .4 ma[—;{ {3 NJ] stung. v — 1'} m Sound: n = 3:13 mfg: I: g = $5, .3— _ Lologmn}, In = 1:14in Fluids: Fe. pw=mfln§§ P=‘—'"-'-, Pm=latm=151kPa1 Pg=P—Pn A P2=P1+pyh. if—ff1 Fan; =pqLZu'u5r. git-2:11: w const, P+£l.:—=+pgy=coust ...
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