exam3key - Chemistry 4511 Physical Chemistry 1 Exam 3...

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Chemistry 4511 Name_________________________ Physical Chemistry 1 Exam 3 Given: Mwa ha ha ha ha! 1 ________________/30 2 a ________________/15 b ________________/10 c ________________/5 3 a ________________/10 b ________________/5 c ________________/5 d ________________/20
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1. (30 pts) Show that for a given gas, the Joule-Thompson Coefficient (μ J ), the heat capacity at a constant volume (C V ), the cubic expansion coefficient ( α ) and the isothermal compressibility ( κ ) are related to one another in the following way: μ J C V = P – ( α T/ κ ) where μ J = U dV dT (hint: you will need the following relationship from linear algebra calculus math place… 1 = x y z dy dz dz dx dx dy ) We begin with T V U V J dV dU dT dU dV dT C = = µ via the chain rule given above we also know that V T dT dP T P dV dU = from the thermodynamic equation of state now by definition, P dT dV V = 1 α and T dP dV V = 1 κ again, from the chain rule, V V dV dP dT dV dT dP T P V = = so, we can substitute into the equation of state such that T P C V J =
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2. For the following reaction:
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This note was uploaded on 10/11/2011 for the course CHEM 4511 taught by Professor Staff during the Spring '08 term at Colorado.

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exam3key - Chemistry 4511 Physical Chemistry 1 Exam 3...

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