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# exam2key - Chemistry 4511 Exam 2 Gas NO N2 O2 fHo kJ/mol...

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Chemistry 4511 Exam 2 Gas f H o S o d e f kJ/mol J/mol K J/mol K J/mol K -2 (x 10 -3 ) J K/mol (x 10 5 ) NO 90.25 210.76 30.03 2.85 -0.78 N 2 0 191.61 28.58 3.77 -0.5 O 2 0 205.138 29.96 4.18 -1.67 R = 8.315 J/K mol

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1. Given the following reaction: 2 NO(g) Æ N 2 (g) + O 2 (g) a. Give the H o , S o , and G o values. (5 pts) H o = S o G o = H – (298) b. Now we adjust the temperature to 1000 K. How does this change G? (15 pts) ∆∆ H = d(T 2 – T 1 ) + e/2 (T 2 2 – T 1 2 ) – f(1/T 2 – 1/T 1 ) d = 28.58 + 29.96 – 2(30.03) = -1.52 e = 4.18 + 3.77 – 2(2.85) = 2.25 x 10 -3 f = -1.67-0.5 – 2(-0.78) = -0.61 x 10 5 ∆∆ H = -1.52(1000-298.15) + 2.25x10 -3 /2 (1000 2 – 298.15 2 ) + 6.1x10 4 (1/1000 – 1/298.15) = -185.41 J/mol H 1000 = H o + ∆∆ H = -180.5 - 0.18541 = -180.685kJ/mol G 1000 c. Let’s assume at some point in time, the reaction has progressed such that ξ = 0.39 when we began with 2 moles of NO. How many moles of each gas are represented? (5pts) ξ = n/ ν = 0.39 = n/-2 Æ n = 0.78 moles so at this time, n NO n N2 = n O2
2. Given the following data table for one mole of a strangely behaving gas, derive the equation of state: (30 pts)

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## This note was uploaded on 10/11/2011 for the course CHEM 4511 taught by Professor Staff during the Spring '08 term at Colorado.

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exam2key - Chemistry 4511 Exam 2 Gas NO N2 O2 fHo kJ/mol...

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