Exam1key - Chemistry 4511 Physical Chemistry I Exam I Given Info R = 8.315 J mol-1 K-1 kb = 1.38 x 10-23 J K-1 Van Der Waals Constants Substance

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Chemistry 4511 Physical Chemistry I Exam I Given Info: R = 8.315 J mol -1 K -1 Van Der Waals Constants k b = 1.38 x 10 -23 J K -1 ab P c T c (J . m 3 /mole 2 )( m 3 /mole) (MPa) (K) Air 0.1358 3.64x10 -5 3.77 133 K Carbon Dioxide (CO 2 ) 0.3643 4.27x10 -5 7.39 304.2 K Nitrogen (N 2 ) 0.1361 3.85x10 -5 3.39 126.2 K Hydrogen (H 2 ) 0.0247 2.65x10 -5 1.3 33.2 K Water (H 2 O) 0.5507 3.04x10 -5 22.09 647.3 K Ammonia (NH 3 ) 0.4233 3.73x10 -5 11.28 406 K Helium (He) 0.00341 2.34x10 -5 0.23 5.2 K Freon (CCl 2 F 2 ) 1.078 9.98x10 -5 4.12 385 K Substance A 0 a B 0 b c Pa m 6 mol -2 10 -6 m 3 mol -1 10 -6 m 3 mol -1 10 -6 m 3 mol -1 10 m 3 mol -1 He 0.00219 59.84 14 0 0.004 Ne 0.02153 21.96 20.6 0 0.101 Ar 0.13078 23.28 39.31 0 5.99 H 2 0.02001 -5.06 20.96 -43.59 0.0504 N 2 0.1362 26.17 50.46 -6.91 4.2 O 2 0.1511 25.62 46.24 4.208 4.8 Air 0.13184 19.31 46.11 -11.01 4.34 CO 2 0.50728 71.32 104.76 72.35 66 CH 4 0.23071 18.55 55.87 -15.87 12.83 Substance
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1. No one can ever say I didn’t make you plug and chug… a. For 0.53 moles of CO 2 in a 1.5L vessel at 300K, assuming the Beattie- Bridgman value for the pressure is the true value, what is the percent error given by the Ideal Gas equation and by Van Der Waals? V m = 1.5/.053 = 2.83 L/mol = .00283 m 3 /mol Beattie-Bridgeman A = 0.50728(1-71.32 x 10 -6 /0.00283) = 0.4945 B = 104.76 x 10 -6 (1-72.35 x 10 -6 /0.00283) = 1.0208 x 10 -4 () 2 2 4 2 3 843558 00283 . 0 4945 . 0 10 0208 . 1 00283 . 0 00283 . 0 300 00283 . 0 660 1 300 315 . 8 = + = m N x P Ideal P = RT/V m = 8.315*300/0.00283 = 881449 N m -2 Van Der Waals 2 2 5 849465 00283 . 0 3643 . 0 10 27 . 4 00283 . 0 300 315 . 8 = = m N x P % error Ideal % 49 . 4 100 843558 843558 881449 = % error VDW % 70 . 0 100 843558 843558 849465 = b. What is u 2 for O 2 at 300K? 2 2 5 2 10 339 . 2 032 . 0 300 315 . 8 3 3 = = = s m x M RT u c. If I said that Fred and Wilma, on average, were moving at 1.32 m/s and 6.77 m/s respectively at the same temperature, then what is the ratio of their masses?
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This note was uploaded on 10/11/2011 for the course CHEM 4511 taught by Professor Staff during the Spring '08 term at Colorado.

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Exam1key - Chemistry 4511 Physical Chemistry I Exam I Given Info R = 8.315 J mol-1 K-1 kb = 1.38 x 10-23 J K-1 Van Der Waals Constants Substance

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