midtermtest12000Solutions

midtermtest12000Solutions - CHEN 3010 Applied Data Analysis...

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CHEN 3010 Applied Data Analysis Fall 2000 Solution to Mid Term Test 1, Version A 1 Eye pressure of the human population is normally distributed with μ = 17; and σ = 3 Therefore, the probability of misdiagnosis as glaucomic when x 22 is PX P x PZ [] = = = < = = 22 17 3 22 17 3 5 3 1 5 3 10 9515 0 0485 .. 2 2.1: Because the sum of the probabilities for all x should be 1, that means 13 3 12 3 05 5 3 1 + + + + + = kk k . Which will lead to 25 10 3 . += k , then k = 005 . 2.2: We know the k, then we can calculate the density of probability as following: 123 fx () 1153 . 113 . 0753 . Therefore, EX = 11 1 5321 1 33 0753 563 . . 22 2 2 1 5 321 1 33 0 7 5 34 1 = . . = = = 2 2 2 41 563 072 . 2.3: The cumulative distribution of x is: Fx . 2253 . 1 3 Maximum daily measurement of CO is a continuos random variable x and follows an exponential distribution, therefore e () = β Here == × = αβ 5 . , therefore = 35 . , then e x = < = = −∞ 10 5 1 10 5 1 1 0 0498 10 5 .
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This note was uploaded on 10/11/2011 for the course CHEN 3010 taught by Professor Kompala,dh during the Spring '08 term at Colorado.

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midtermtest12000Solutions - CHEN 3010 Applied Data Analysis...

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