Homework03Solutions

Homework03Solutions - CHEN 3010 Applied Data Analysis...

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CHEN 3010 Applied Data Analysis Fall 2004 Homework 03 Solutions Problem 1 3-34. a) P(X > x) = 1 – P(X < x) = 1 - PZ x < 6 3 = 0.50. And, x < 6 3 = 0.50 Therefore, 3 6 x = 0 and x = 6. b) P(X > x) = 1 – P(X < x) = 1 - x < 6 3 = 0.95. And, x < 6 3 = 0.05 Therefore, 3 6 x = -1.645 and x = 1.065. c) P(x < X < 9) = 0.20 P x ZP x Z x x x x << = < < = < = < = < = 6 3 96 3 6 3 1 1 6 3 020 0 841345 6 3 6 3 0 841345 0 20 6 3 0 641345 () . .. . Therefore, 3 6 x =0.36, and x = 7.08. d) P(3 < X < x) = 0.80 x x x x x 36 3 6 3 1 6 3 6 3 10 8 0 6 3 0 158655 0 80 6 3 0 958655 = < < = < = < = . . Therefore, x 6 3 1.74, and x = 11.22.
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CHEN 3010 Applied Data Analysis Fall 2004 Problem 2 3-46. a) P(X > 2.10) = P(Z > 2) = 1 – P(Z < 2) = 1 – 0.977250 = 0.02275 b) P(X < 2.10) = 0.999 PZ < = = = 210 2 0 999 31 0 03226 .
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This note was uploaded on 10/11/2011 for the course CHEN 3010 taught by Professor Kompala,dh during the Spring '08 term at Colorado.

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Homework03Solutions - CHEN 3010 Applied Data Analysis...

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