2. The internal resistance of the battery is approximately
0.8375 ohms.
3. The yintercept of this line, or E’=1.3661.
4. The percentage difference from the actual EMF of the battery is (abs(1.35
1.3661)/1.3661)*100= 0.0118 %
8.1.2 Batteries in Series I
1.
V=EIr
r = {(VE)/I}
r = (4.08 V 4.31 V)/ 0.08A = 2.8
Ω
2.
E’ = E1+E2+E3 = 1.33 V+1.48 V+1.47 V = 4.28 V
3.
Percent Difference = {abs(EE’)/E’}x100 %
{abs(4.31 V4.28 V)/4.28 V}x100% = 0.7 %
4.
Internal resistance combined (r) = 2.8
Ω
Individual battery resistance (2.8
Ω
/3) = 0.93
Ω
0.8375
Ω
was what was found in 8.1.1, which differs by 0.093
Ω
, which seems to be
consistent on how the resistance of the batteries also add up.
8.1.3 Batteries in Series II
1.
V=EIr
r = {(VE)/I}
r = (1.26 V 1.35 V)/ 0.027A = 3.33
Ω
The combined total resistance of the batteries is 3.33 ohms.
2.
E1= 1.33 V
E2=1.48 V
E3=1.47 V
E’(total)=1.33 V+1.48 V+(1.47 V)=1.34 V
3. Percent Difference = {abs(EE’)/E’}x100 %
{abs(1.35 V1.34V)/1.34 V}x100% = 0.75 %
4.
Internal resistance combined (r) = 3.33
Ω
Individual battery resistance (3.33
Ω
/3) = 1.11
Ω
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
The total resistance is EV/I=R so, 1.35 V1.26 V/.027 A=3.33
Ω
/3=1.11 ohms.
This
value is pretty similar to the value I obtained in 8.1.1, which was 0.8375 ohms.
This is the end of the preview.
Sign up
to
access the rest of the document.
 Spring '11
 long
 Batteries, Electrical resistance, internal resistance, Individual battery resistance, 0.0118 %

Click to edit the document details