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Lab 8 data - 2 The internal resistance of the battery is...

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2. The internal resistance of the battery is approximately 0.8375 ohms. 3. The y-intercept of this line, or E’=1.3661. 4. The percentage difference from the actual EMF of the battery is (abs(1.35- 1.3661)/1.3661)*100= 0.0118 % 8.1.2 Batteries in Series I 1. V=E-Ir r = {(V-E)/I} r = (4.08 V- 4.31 V)/ 0.08A = 2.8 2. E’ = E1+E2+E3 = 1.33 V+1.48 V+1.47 V = 4.28 V 3. Percent Difference = {abs(E-E’)/E’}x100 % {abs(4.31 V-4.28 V)/4.28 V}x100% = 0.7 % 4. Internal resistance combined (r) = 2.8 Individual battery resistance (2.8 /3) = 0.93 0.8375 was what was found in 8.1.1, which differs by 0.093 , which seems to be consistent on how the resistance of the batteries also add up. 8.1.3 Batteries in Series II 1. V=E-Ir r = {(V-E)/I} r = (1.26 V- 1.35 V)/ 0.027A = 3.33 The combined total resistance of the batteries is 3.33 ohms. 2. E1= 1.33 V E2=1.48 V E3=-1.47 V E’(total)=1.33 V+1.48 V+(-1.47 V)=1.34 V 3. Percent Difference = {abs(E-E’)/E’}x100 % {abs(1.35 V-1.34V)/1.34 V}x100% = 0.75 % 4. Internal resistance combined (r) = 3.33 Individual battery resistance (3.33 /3) = 1.11
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The total resistance is E-V/I=R so, 1.35 V-1.26 V/.027 A=3.33 /3=1.11 ohms. This value is pretty similar to the value I obtained in 8.1.1, which was 0.8375 ohms.
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