125_201+Homework-2+soln

125_201+Homework-2+soln - 125:201 Introduction to...

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125:201 Introduction to Biomedical Engineering Biomechanics, Homework #2 Due Monday October 25 th Problem 1 A) Find the joint reaction force, R, and the abductor muscle force, M, in the right hip when a woman stands on her right leg while carrying a 25kg suitcase in the left hand (Fig 7.7A). You can use the following data: Body weight = 600N Weight of standing leg = 100N Moment arm of the weight of the suitcase = 0.31m Moment arm of the abductor muscle force = 0.05m Moment arm of the body weight = 0.05m Moment arm of the body weight excluding the standing leg = 0.06m Moment arm of the standing leg = 0.01m (medial to the joint) Moment arm of the ground reaction force = 0.06m (medial to the joint) Abductor muscle force (M) acts at a 70 degree angle to the transverse plane. B) Find R and M for the right hip joint when the woman stands on the right leg while carrying a 25kg suitcase in each hand (Fig 7.7b). The moment arm for the weight of the suitcase in her right hand is 0.14m. All other weights and dimensions are as above. Which produces a larger hip joint reaction force: carrying 25kg in one hand or 50kg evenly distributed between two hands. Does the distribution of the burden have sufficient effect on the joint reaction force to justify its mention during ergonomic counseling? In other words, does it make more sense to carry twice the load?
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Problem 1: For this problem there are several ways to solve it. I will first solve it using the ‘rest of body’ approach. A) We can first draw a free body diagram of the body excluding the leg
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This note was uploaded on 10/11/2011 for the course BIOMEDICAL 201 taught by Professor Berth during the Fall '10 term at Rutgers.

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125_201+Homework-2+soln - 125:201 Introduction to...

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