Unformatted text preview: are met. Suppose Metaltech decided to use a 5% level of significance and the observed sample mean is 30.5 feet with the sample variance 16 feet 2 . Perform the appropriate test. Claim: σ 2 ≤ 12 H : σ 2 ≤ 12 vs. H 1 : σ 2 > 12 s 2 = 16. n = 25. Test Statistic: ( 29 ( 29 12 16 1 25 1 2 2 2 s ⋅ σ ⋅ χ== n = 32 . Rejection Region: Right – tailed. Reject H if 2 2 α χ χ n – 1 = 24 degrees of freedom. α = 0.05 2 05 . χ = 36.42 . Reject H if 2 χ > 36.42. The value of the test statistic does not fall into the Rejection Region. Do NOT Reject H at α = 0.05 ....
View
Full Document
 Spring '11
 Stepanov
 Statistics, Normal Distribution, Variance, Probability theory, Metaltech

Click to edit the document details