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Unformatted text preview: Let μ = this year’s overall mean SAT score. Claim: μ > 1100. H : μ ≤ 1100 vs. H 1 : μ > 1100 . Right – tailed. Rejection Region : Reject H if Z = n σ μ X> z α ⇒ Z = 81 72 1100 X> 1.645 ⇒ 81 72 645 . 1 1100 X ⋅ + = 1113.16 . Power ( μ = 1111 ) = P ( Reject H  H is NOT true ) = P ( X > 1113.16  μ = 1111 ) = 81 72 1111 16 . 1113 Z P = P ( Z > 0.27 ) = 1 – Φ ( 0.27 ) = 1 – 0.6064 = 0.3936 ....
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This note was uploaded on 10/12/2011 for the course STATISTICS stat 410 taught by Professor Stepanov during the Spring '11 term at University of Illinois, Urbana Champaign.
 Spring '11
 Stepanov
 Standard Deviation

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