Assignment_1_sol - CollegeofEngineering,QatarUniversity...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
College of Engineering, Qatar University Probability and Statistics, GENG200 2BS Sample Solution Assignment – 1 Questions: 2-37; 2-38; 2-39; 2-40; 2-41; 2-45; 2-46 2-66; 2-69; 2-73 2-75; 2-78; 2-84 2-94; 2-98 Answer: 2-37. From the multiplication rule, 144 4 3 4 3 = × × × 2-38. From equation 2-1, the answer is 10! = 3,628,800 2-39. From the multiplication rule and equation 2-1, the answer is 5!5! = 14,400 2-40. From equation 2-3, 35 ! 4 ! 3 ! 7 = sequences are possible 2-41. a) From equation 2-4, the number of samples of size five is ( ) 528 , 965 , 416 ! 135 ! 5 ! 140 140 5 = = b) There are 10 ways of selecting one nonconforming chip and there are ( ) 880 , 358 , 11 ! 126 ! 4 ! 130 130 4 = = ways of selecting four conforming chips. Therefore, the number of samples that contain exactly one nonconforming chip is 10 ( ) 800 , 588 , 113 130 4 = × c). The number of samples that contain at least one nonconforming chip is the total number of samples ( ) 140 5 minus the number of samples that contain no nonconforming chips
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 10/12/2011 for the course STATISTICS 101 taught by Professor Nazim during the Spring '10 term at Qatar University.

Page1 / 3

Assignment_1_sol - CollegeofEngineering,QatarUniversity...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online