IRWIN 9e 4_FE-5 - 3 = + + k V R V V R V o i o o 2 Irwin,...

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Irwin, Basic Engineering Circuit Analysis, 9/E 1 Chapter 4: Operational Amplifiers Problem 4.FE-5 SOLUTION: k 2 k 8 + - = k R 6 1 = k R 2 2 = k R 1 3 V 5 + o V The correct answer is c . The 8k and 2k resistors make up a noninverting op-amp. V k k V 25 5 2 8 1 1 = + = Use nodal analysis at node A: 0 2 25 1
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Unformatted text preview: 3 = + + k V R V V R V o i o o 2 Irwin, Basic Engineering Circuit Analysis, 9/E Problem 4.FE-5 Chapter 4: Operational Amplifiers 2 25 6 5 1 = + + k V k V k V o o o 75 3 5 6 = + + o o o V V V 80 10 = o V V V o 8 =...
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This note was uploaded on 10/12/2011 for the course ELEE 2320 taught by Professor Foltz,h during the Spring '08 term at Texas Pan American.

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IRWIN 9e 4_FE-5 - 3 = + + k V R V V R V o i o o 2 Irwin,...

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