IRWIN 9e 5_2 - Inn/in Basic Engineering Circuit Analysis...

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Unformatted text preview: Inn/in, Basic Engineering Circuit Analysis, 9/E ‘ 1 52 Find 1;, in the new-furl; in Fig. 135.2 using [insanityr and the assumption that In = 1 ma. 2H1 2m Emilio 2H1]. Eliflkfikfl Flgu re P53 SOLUTION: 2 2m 1 2m 2k!) A5$mb IO = 1m“ v, = Io (4k) = 1m£4i<)=4v KCLati'. =V I+V :3...- i!‘ 4'=+A I :2—Ll ” 2:1: 2k "" “+24: "’ KVL WM mfoldtc 1,0 ; KCL cucz I = __v,_.__ =42. :. i.+4m = Iowa 4 2k *1 k «QK ___—_______.____—_—_—._—_—————————————-——-— Chapter 5: Additional Analysis Techniques Problem 5.2 " ...
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