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IRWIN 9e 5_103

# IRWIN 9e 5_103 - lrwin Basic Engineering Circuit Analysis...

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Unformatted text preview: lrwin, Basic Engineering Circuit Analysis, 91E 1 5.103 Fiml RL i'ur maximum [Him-w transfer and the maximum power that can he transferred in the Jihad in Fig. Pililﬁ. 1 mA Figure P5403 SOLUTION: 5 Chapter 5: Additional Analysis Techniques Problem 5.103 2 Irwin, Basic Engineering Circuit Analysis, 9/E KCL or \lx‘. 1m: \/><_ V1- V0 1k ﬁr 2i. 3VI‘V0= 2 KCLax V0: Vx-Vo : 4V3 +_\[b_ 2L 1000 3k Z! V“, -i- 5V0 = 0 V1. 0‘218V V0... -1.ie7v Ln = _\_/o_ : —I-l6'r’ , -0-38‘ImA 3 3k. 3 "il4 = B'Gk—D— ——O-38‘1m pm. maxfmum Fwy}. Xi’an/lift.) EL: 2TH: , Problem 5.103 Chapter 5'. Additional Ana|ysis Techniques Irwin, Basic Engineering Circuit Analysis, 9/E 3 IL -_:. ’1'4" 3-GL+ 3.6k = —- 0'194-mA P = If KL ... (- 0494973519: O'l36mN _____—____—_______—__—_.__——————-——————— Chapter 5: Additional Analysis Techniques Problem 5.103 ...
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