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IRWIN 9e 5_106 - Irwin Basic Engineering Circuit Ana|ysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Ana|ysis, 9/E 1 5.1135- Fiud Ihc maximum rim-w 11ml cam he ii'anat'erreil in RL in the network 01' Fig. P5. llifi. {Li 'L" 12 V [i' Figure P5406 SOLUTION: \/o = 1000 I Chapter 5: Additionaii Analysis Techniques Problem 5.106 2 Irwin, Basic Engineering Circuit Analysis, 9/E L0. = I) ‘ 1:. KVL WWW/06¢: £9072: 0‘5l/o = 5001, +500Il V0: 20001, KVL M N: Loaf): \/o= 12v l<\/L 3w Loaf: 11: 10001; I}; 12w: KL: as m EL: RT” = 669.12,pr maxfmww Fwwimmrfw. V :. (6 4" s” L :6? a 6‘4 Q0 4') 1V PL: :fiflx = KL as; Problem 5.106 Chapter 5: Additional Analysis Techniques ...
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