Ch4_D_Formulas

# Ch4_D_Formulas - Using Stoichiometry to Determine a Formula...

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Unformatted text preview: Using Stoichiometry to Determine a Formula Burn 0.115 g of a hydrocarbon, C xHy, and produce 0.379 g of CO 2 and 0.1035 g of H2O. What is the empirical formula of CxHy? CxHy + some oxygen ---> 0.379 g CO 2 + 0.1035 g H 2O 0.379 Using Stoichiometry to Determine a Formula Using Stoichiometry to Determine a Formula CxHy + some oxygen ---> 0.379 g CO2 + 0.1035 g H2O 0.379 CxHy + some oxygen ---> 0.379 g CO2 + 0.1035 g H2O 0.379 First, recognize that all C in CO 2 and all H in H2O is from CxHy. Now find ratio of mol H/mol C to find values of x and y in C xHy. 1. Calculate moles of C in CO 2 -2 mol 1.149 x 10 -2 mol H/ 8.61 x 10 -3 mol C 1.149 mol 8.61 x 10-3 mol C mol = 1.33 mol H / 1.00 mol C Calculate moles of H in H 2O = 4 mol H / 3 mol C -2 mol 1.149 x 10 -2 mol H 1.149 Empirical formula = C 3H4 2. Page 1 ...
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