CH 9 worksheet KEY

CH 9 worksheet KEY - CH 9 Worksheet CHM 1025 Name KEY 1 How many particles are in the following a 12.56 mol C x(6.022 x 1023 atoms C 1 mol C =

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CH 9: Worksheet Name: KEY CHM 1025 1. How many particles are in the following? a. 12.56 mol C x (6.022 x 10 23 atoms C / 1 mol C) = 7.564 x 10 24 atoms C b. 0.489 mol Na + x (6.022 x 10 23 ions Na + / 1 mol Na + ) = 2.94 x 10 23 Na + ions c. 1.56 x 10 3 mol CO 2 x (6.022 x 10 23 molecules CO 2 / 1 mol CO 2 ) = 9.39 x 10 26 molecules CO 2 d. 78.3 mol Cl - x (6.022 x 10 23 ions Cl - / 1 mol Cl - ) = 4.72 x 10 25 ions Cl - e. 6.35 x 10 -5 mol H 2 O x (6.022 x 10 23 molecules H 2 O / 1 mol H 2 O) = 3.82 x 10 19 molecules H 2 O 2. How many moles are in the following? a. 5.6 x 10 34 atoms of Fe x (1 mol Fe / 6.022 x 10 23 atoms Fe) = 9.3 x 10 10 mol Fe b. 45.68 molecules of O 2 x (1 mol O 2 / 6.022 x 10 23 molecules O 2 ) = 7.586 x 10 -23 mol O 2 c. 7.98 x 10 12 ions of F - x (1 mol F - / 6.022 x 10 23 ions F - ) = 1.33 x 10 -11 mol F - d. 84235 ions of Mg 2+ x (1 mol Mg 2+ / 6.022 x 10 23 ions Mg 2+ ) = 1.3988 x 10 -19 mol Mg 2+ 1
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Calculate the molar mass for the following a. C 6 H 12 = 6(12.011) + 12(1.008) = 84.162 g/mol b. FeCl 3 = 1(55.85) + 3(35.453) = 162.21 g/mol c. Br 2 = 2(79.90) = 159.8 g/mol d. NaOH = 1(22.990) + 1(15.994) + 1(1.008) = 39.997 g/mol e. Ca(NO 3 ) 2 = 1(40.08) + 2(14.007) + 6(15.9994) = 164.09 g/mol 4. Calculate the mass of the following a. 1.56 x 10 3 mol C 6 H 12 x (84.162 g C 6 H 12 / 1 mol C 6 H 12 ) = 1.31 x 10 5 g C 6 H 12 b. 32 mol FeCl 3 x (162.21 g FeCl 3 / 1 mol FeCl 3 ) = 5.2 x 10 3 g FeCl 3 c. 6.21 x 10 -3 mol Br 2 x (159.8 g Br 2 / 1 mol Br 2 ) = 9.92 x 10
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This note was uploaded on 10/20/2011 for the course CHEM 1025 taught by Professor Smith during the Spring '10 term at Valencia.

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CH 9 worksheet KEY - CH 9 Worksheet CHM 1025 Name KEY 1 How many particles are in the following a 12.56 mol C x(6.022 x 1023 atoms C 1 mol C =

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