lecture25 - Self-Inductance and Circuits Self-Inductance...

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Self-Inductance and Circuits Self-Inductance and Circuits  Inductors in circuits  RL circuits
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Inductors in Series and Parallel L T  = L 1  +L 2 …. 1/L T  = 1/L 1  + 1/L 2
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Self-Inductance Self-Inductance dt dI L L - = ε I 2 2 1 LI U L = Potential energy stored in an  inductor: Self-induced emf:
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RL circuits: current increasing RL circuits: current increasing The switch is closed at t =0;  Find I (t). - = - = = - - I R L R L IR dt dI IR dt dI L ε 0 ε L R I Kirchoff’s loop rule:
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Solution Solution     R L = τ Time Constant: Note that H/  = seconds Ω (show as exercise!) ( 29 ε / 1 ) ( t e R t I - - =
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0 1 τ 2 τ 3 τ 4 τ 63% ε /R I t Time Constant: Current Equilibrium Value:  R L = τ ( 29 ε / 1 ) ( t e R t I - - = R I =
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Example 1 Calculate the inductance in an RL circuit in which R=0.5 and the current increases to one fourth of its final value  in 1.5 sec.
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L R I RL circuits: current decreasing Assume the initial current I 0  is known. Find the  differential equation for I(t) and solve it.
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This note was uploaded on 10/14/2011 for the course ENGINEER CHEM ENG 3 taught by Professor Ghosh during the Spring '11 term at McMaster University.

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lecture25 - Self-Inductance and Circuits Self-Inductance...

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