This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: T F Physics 53 Summer 2010 1 3. A bicycle rider travels along a straight road at a constant speed of 5 m/s. Just as she passes a golfer in a golf cart at rest, the golfer starts to accelerate at a constant rate of 2 m/s 2 to overtake her. a. Find the time it takes the golf cart to draw even with the bike. b. Find the speed of the golf cart at this time. c. Find how far the golf cart travels before it draws even with the bike. a. For the bike: x b = 5 t . For the cart: x c = 1 2 ⋅ 2 t 2 . Set these equal: 5 t = t 2 . The two roots are t = , which is when the bike passes the cart, and t = 5 s, which is when the cart catches (and passes) the bike. b. For the cart: v c = 2 t , so at t = 5 we have v c = 10 m/s. c. When t = 5 we have x c = 25 m. Physics 53 Summer 2010 2...
View Full Document
This note was uploaded on 10/19/2011 for the course PHYSICS 53L taught by Professor Mueller during the Spring '07 term at Duke.
- Spring '07