assignment#2

assignment#2 - f) No the events in parts a and b are not...

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Elisa Chan 260326747 3.24 a) The sample points are boy-boy, boy-girl, girl-boy and girl-girl. b) .25 for each (1/2 x ½ = ¼ ) c) boy-boy .257 boy- girl .258 girl-boy .26 girl-girl .22 Yes the estimates agree with what we found in part b of .25 to a reasonable amount. d) The results here indicate that boys do not necessarily run in the family and that the probability of both sexes are pretty equal. 3.32 a) the probability of randomly selecting a child with blue eyes is ¼ . b) If one parent is heterozygous Bb and the other has blue eyes, the probability of selecting a child with blue eyes is 1/2. c) If a parent is homozygous for brown eyes (BB), then there is 0 probability of selecting a child with blue eyes. 3.56 a)1307/7488 = .1745 that the offender has a gang score of 5. b) 1438/7488 = .192 c) (2806 + 670+787 ) / 7488 = .233 d) 476/ 7488 = 0.064 e) 2551/7488 = .341
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Unformatted text preview: f) No the events in parts a and b are not mutually exclusive because it is possible for an offender to have both a gang score of 5 and carry a weapon. g) the events in parts a and c are mutually exclusive because an offender cannot have both a gang score of 5 and a gang score below 3. It is either a gang score of 5 or a gang score of 3. 3.138 A = actual detection. Therefore the probability that the actual defect exists when the NDE detects a hit is 0.9996. <li> 3.150 a) Urn 1 has 1/6 chance of being drawn from. Urn 2 has 5/6 chance of being drawn from. Urn 1 has .4 chance of red ball. Urn 2 has .6 chance of red ball. So (1/6) * .4 = probability of getting red ball from urn 1 = 0.067 (5/6) * .6 = prob. of red ball from urn 2 = 0.5. Total chance of getting red ball = 0.567 b) Given that a red ball was drawn then the chance of urn 1 being drawn is 3.178...
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This note was uploaded on 10/12/2011 for the course MATH 203 taught by Professor Dr.josecorrea during the Spring '08 term at McGill.

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assignment#2 - f) No the events in parts a and b are not...

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