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Unformatted text preview: the third one must be. If we set x = 0 = y, then substitution into the equation yields z = 5 , so we can use as our basepoint P (0 , , 5) (which is the intersection of P with the z-axis). We could nd the intersections of P with the other two axes in a similar way. Alternatively, we could notice that x = 1 y = 1 means that 2 x 3 y = 5 , so z = 0 and we could equally well use as our basepoint P (1 , 1 , 0) ....
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- Fall '08