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Unformatted text preview: (e) It then follows by Proposition III.22 of the Elements (opposite angles of a quadrilateral inscribed in a circle sum to two right angles) that CLB + COB equals two right angles. Show that BOC + AOF equals two right angles. ( Hint: Each of the lines from O to a vertex of ABC bisects the angle there.) It follows that CLB = AOF....
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This note was uploaded on 10/20/2011 for the course MAC 2311 taught by Professor All during the Fall '08 term at University of Florida.
 Fall '08
 ALL
 Calculus

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