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Engineering Calculus Notes 123

# Engineering Calculus Notes 123 - 1 x = − 2 t y = 1 − 2...

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1.7. APPLICATIONS OF CROSS PRODUCTS 111 (b) P contains the three points P (4 , 5 , 6) Q (3 , 2 , 7) R (5 , 1 , 1) . (c) P contains P (3 , 1 , 4) and the line x = 1 + t y = 2 +2 t z = 3 t. (d) P is parametrized by x = 1 2 s +3 t y = 2 s + t z = 2 + s + t. 2. Give a parametrization of each plane P described below: (a) P contains the three points P (3 , 1 , 2) Q (2 , 1 , 1) R (8 , 3 , 1) . (b) P contains the lines
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Unformatted text preview: 1 : x = − 2 + t y = 1 − 2 t z = 4 + t ℓ 2 : x = − 1 +2 t y = − 1 + t z = 5 − 3 t . (c) P meets the plane 3 x + y + z = 2 in the line x = 1 − t y = 2 + t z = − 3 +2 t and is perpendicular to it....
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