Unformatted text preview: 124 CHAPTER 2. CURVES To ﬁx ideas, let us place the y -axis along the directrix and the focus at a
point F (k, 0) on the x-axis. The distance of a generic point P (x, y ) from
the y -axis is |x|, while its distance from the focus is
|F P | = (x − k)2 + y 2 . Thus the focus-directrix property can be written
|F P |
where e is the eccentricity. Multiplying through by |x| and squaring both
sides leads to the equation of degree two
(x − k)2 + y 2 = e2 x2 .
which can be rewritten
(1 − e2 )x2 − 2kx + y 2 = −k2 . (2.8) Parabolas
When e = 1, the x2 -term drops out, and we have
y 2 = 2kx − k2 = 2k x − k
2 . (2.9) Now, we change coordinates, moving the y -axis k/2 units to the right. The
eﬀect of this on the equation is a bit counter-intuitive. To understand this,
let us ﬁx a point P whose coordinates before the move were (x, y ); let us
for a moment denote its coordinates after the move by (X, Y ). Clearly,
since nothing moves up or down, Y = y . However, the new origin is k/2
units to the right of the old one—or looking at it another way, the new
origin was, in the old coordinate system, at (x, y ) = (k/2, 0), and is now
(in the new coordinate system) at (X, Y ) = (0, 0); in particular,
X = x − k/2. But this eﬀect applies to all points. So if a point is on our
parabola—that is, if its old coordinates satisfy Equation (2.9), then
rewriting this in terms of the new coordinates we get Y 2 = 2kX .
Switching back to using lower-case x and y for our coordinates after the
move, and setting
p = 2k,
we recover Equation (2.4)
y 2 = px ...
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This note was uploaded on 10/20/2011 for the course MAC 2311 taught by Professor All during the Fall '08 term at University of Florida.
- Fall '08