Unformatted text preview: , to get 2 x dx dy + 8 y = 0 . Upon substituting x = 2 √ 2, y = 0, this yields 4 √ 2 dx dy + 0 = 0 which does have a solution, dx dy = 0 . In this case, we can see the reason for our di²culty by explicitly solving the original equation ( 3.12 ) for y in terms of x : near (2 , − 1), y can be...
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This note was uploaded on 10/20/2011 for the course MAC 2311 taught by Professor All during the Fall '08 term at University of Florida.
 Fall '08
 ALL
 Calculus

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