Unformatted text preview: [ Q ] = 1 − 1 − 1 and it is easy to calculate that Δ 1 = det[ Q ] = (1)( − 1)( − 1) = 1 > ...which, so far, tells us that the form is not negative deFnite. .. Δ 2 = (1)( − 1) = − 1 < so that Q is also not positive deFnite. There is no further information to be gained from calculating Δ 1 = 1 . 2. The form Q ( x,y,z ) = 2 xy + 2 xz + 2 yz has matrix representative [ Q ] = 0 1 1 1 0 1 1 1 0...
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This note was uploaded on 10/20/2011 for the course MAC 2311 taught by Professor All during the Spring '08 term at University of Florida.
 Spring '08
 ALL
 Calculus, Determinant

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