Lect_6oct13f09

Lect_6oct13f09 - Outline 6 13-OCT-2009 1. Review Names,...

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1 Outline 6 13-OCT-2009 1. Review – Names, Molecular Mass, Molar Mass, Moles, Formulas (mole ratios) 2. Calculating Formulas (cont.) Indirect (Combustion) Analysis 3. Writing Chemical Equations Balancing (Conservation of Mass) 4. Stoichiometry (Chem. Eqn.) Mass A→ Mol A → Mol B → Mass B
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2 1.Same group elements may have similar compounds. Ex: S & Se Group VIA; SO 4 -2 (sulfate ion) so SeO 4 -2 (selenate ion) Cl & Br Group VII; HClO 2 (aq) , chlorous acid so ClO 2 - (chlorite ion) HBrO 2 (aq), bromous acid so BrO 2 - (bromite ion) 2. Oxoanions – names relative BrO 2 - (bromite ion) so BrO - (hypobromite ion) BrO 3 - (bromate ion) so BrO 4 - (perbromate ion) SeO 4 - 2 (selenate ion) so SeO 3 - 2 (selenite ion)
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3 Previous ion patterns most important , but note these! 1. Non-metallic Cations (-onium implies positive) NH 4 + ammonium ion H 3 O + hydronium ion (associated with acids) 2. Non-monatomic Anions Ending in -ide OH - hydroxide ion (-ide implies negative) CN - cyanide ion O 2 2- peroxide ion 3. Organic Anion C 2 H 3 O 2 - , acetate ion 4. Metal containing oxoanions CrO 4 -2 chromate ion, Cr 2 O 7 -2 dichromate ion MnO 4 - permanganate ion (manganate is MnO 4 2- !?) (Bold face indicates relative importance.)
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4 Ex: classify (Ionic, Molecular, Acid) to help write formula or name. 1. iron (III) sulfate 2. sulfurous acid 3. HF • 4. Na 3 PO 4 5. sulfur trioxide • 6. NI 3 7. aluminum carbonate • 8. N 2 O 4
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5 (last class) Atomic World 1 molecule H 2 O 18 amu Our World = 6.02 * 10 23 * atomic world 1 mole H 2 O 18 g Means that 6.02 * 10 23 * amu = 1.00 g (because 18 amu* 6.02 * 10 23 = 18 g)
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6 One mole of any element (compound) weighs its atomic (formula) mass in grams . Ex: One molecule CO 2 44.0 amu/molecule One mole CO 2 44.0 g/mol Moles mass conversion necessary for understanding quantitative nature of chemical equations. STOICHIOMETRY. GO FOR THE MOLES!
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7 Ex: Suppose have 5.75 moles of magnesium (Mg, 24.3 g/mol). What is its mass? g/mol) (24.3 moles) 75 . 5 ( Mg mass × = Mg of grams 140 = Use units!
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8 Mole calculations (Cont.) mass → moles → molecules Given: 100.0 grams of N 2 O 5 Find: (a) molar mass, (b)# mol (c) # molecules (a)2 mol N*14.0 g/mol N+ 5 mol O*16.0 g/mol O = 108.0 g so 108.0 g/mol N 2 O 5 (b) # mole N 2 O 5 = 100.0 g N 2 O 5 * (1 mol/108.0 g N 2 O 5 ) = 0.926 mol N 2 O 5 (c) # molecules = 0.926 mol* (6.02*10 23 molecules/mol) = 5.57*10 23 molecules
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9 Review: Mole vs. Molecule molecular mass = 1 *12.01 amu + 4 * 35.45 amu = ? amu
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This note was uploaded on 10/14/2011 for the course CHEM 1A taught by Professor Okamura during the Spring '08 term at UC Riverside.

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Lect_6oct13f09 - Outline 6 13-OCT-2009 1. Review Names,...

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