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Unformatted text preview: z 0.05 = – 1.645. Decision: The value of the test statistic is in the Rejection Region. Reject H at α = 0.05. b) (5) Suppose also that in a random sample of 80 female customers, 48 ordered fries with their burgers. Find the pvalue of the test H : p M = p F vs. H 1 : p M > p F . 120 84 Y 1 1 1 ˆ = = n p = 0.70. 80 48 Y 2 2 2 ˆ = = n p = 0.60. 66 . ˆ 200 132 80 120 48 84 Y Y 2 1 2 1 = = + + = + + = n n p . Test Statistic: Z = +⋅ ⋅ 80 1 120 1 34 . 66 . 60 . 70 . = 1.46 . Pvalue: Right – tailed. Pvalue = ( area of the right tail ) = P( Z ≥ 1.46 ) = 0.0721 ....
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 Fall '11
 STEPHANOV
 Statistics, Harshad number, Statistical hypothesis testing, 5%, Statistical significance

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