Exam1Solutions - Exam 1 Physics 262 Fall 2011 Exam #1 Name:...

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Physics 262 Fall 2011 Exam #1 Name: CLOSED BOOK, CALCULATORS ONLY USE A RULER! SHOW ALL WORK! Use extra blank sheets if necessary c 2 = 1 ε O μ O , S = 1 μ O E × B , I = S , c = 3.00 × 10 8 ms 1 ε O = 8.85 × 10 12 CV 1 m 1 EXTRA CREDIT (Save for last) (10 points) 5 Points: A circular metal loop antenna can be oriented so that the metal loop is in the xy, xz or yz planes. Which orientation will receive the highest signal for the electromagnetic wave with the polarization shown? 5 Points: Which of Maxwell’s Equations describes how this antenna works (Hint: the response of this antenna depends on the rate of change of the electromagnetic Felds). ORIENT the Antenna loop in the XY Plane so that ±araday’s Law applies: E i d l = d Φ B dt = d B i d A ( ) dt Exam 1 1 1 s + 1 s = 2 R , 1 s + 1 s = 1 f , n 1 sin θ 1 = n 2 sin θ 2 Metal loop antenna
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1) (25 points) The laser pointer I use in class operates at a wavelength of 670 nm with a power of 0.500 mW spread uniformly over a circle 1.20 mm in diameter. It is also waterproof. Assuming my laser pointer works in air and in water, Fll in the following table. Water has an index of refraction of n=1.33 Exam 1 2 Air Water Wavelength, λ 670 nm λ =670 nm/n=504 nm Frequency, f f λ =c, f=c/ λ =4.48x10 14 Hz f λ =c, f=c/ λ =4.48x10 14 Hz Angular Frequency, ω ω =2 π f=2.81x10 15 s -1 ω =2 π f=2.81x10 15 s -1 Wavenumber, k k=2 π / λ =9.38x10 6 m -1 k=2 π n/ λ =1.25x10 7 m -1 Period, T T=1/f=2.23x10 -15 s T=1/f=2.23x10 -15 s
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Exam1Solutions - Exam 1 Physics 262 Fall 2011 Exam #1 Name:...

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