Final sol 2007

# Final sol 2007 - Solution a As the aperture is placed at...

This preview shows pages 1–4. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Solution: a). As the aperture is placed at the image plane, from the Gaussian formula, we have: mm s s f n s n s n i i r air i air o air 150 50 1 1 75 1 = ⇒ = + ⇒ = + b). Also from the Gaussian formula: mm s s f n s n s n o o o air i air o air 625 . 10 10 1 10 160 1 1 = ⇒ = + + ⇒ = + c). Case 1.      -- =             +-- +-- =        - ⋅       ⋅        - = 9 . 3 37 . 245 5 . 23 1 245 1 245 1 245 245 1 1 1 1 1 245 1 1 1 1 r o r o r o o r f f f f f f f f M ELEC308 (Spring 2007) Final Exam TA solution Case 2       =              - ⋅       ⋅        - ⋅       = 03125 . 37 . 32 1 625 . 10 1 1 10 1 1 1 245 1 1 50 1 1 1 150 1 M d). Case 1 16 625 . 10 170 '- =- =- = o o o s s m 2 75 150 '- =- =- = r r r s s m 32 = ⋅ = r o system m m m Case 2 Since the object plane and the CCD camera are conjugate, B=0, that indicate A is the magnification of the system. 32 = = A m system e). In the CCD camera, the sample will be a pattern of square grids with line to line spacing of 128um, and it locates in a circle with 2mm diameter. Since the diameter of the aperture is larger than the wavelength greatly, we don’t need to consider the diffraction. Solution: Assume the phase shift is δ ,and sin ka δ θ = , where a is the distance between two slits. For the maxima, we have the equation: 1 1 sin 2 k a m θ π = , then 1 1 sin a m θ λ = For the minima, we have the equation: 2 2 1 sin 2( ) 2 k a m θ π =- , then 2 2 1 sin ( ) 2 a m θ λ =- The Fourth minima of 2 λ light coincides with the third maxima of 1 λ light, We get 1 1 2 2 1 ( ) 2 m m λ λ =- , it is known that 1 3 m = , 2 4 m = and 2 436 nm λ = , therefore, 1 508.6 nm λ = Solution:...
View Full Document

{[ snackBarMessage ]}

### Page1 / 9

Final sol 2007 - Solution a As the aperture is placed at...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online