HW4 solution

# HW4 solution - vt x k provided that we factor out ti i t n...

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Problem 1 ELEC308 (Spring 2008) Assignment 4 TA solution

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Problem 2 (problem 3.7 on page 82) Problem 3 3.14 Total power is 20W; total area at ) ( 4 1 4 0 . 1 2 2 m m π = × = ; 2 56 . 1 4 20 m W area power I = = = 3.19
Problem 4

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Problem 5 4.40 From Snell’s law 0 748 . 12 = t θ ; from Eq.(4.42) and Eq.(4.43)
2352 . 0 748 . 32 sin 252 . 7 sin 1978 . 0 748 . 32 tan 252 . 7 tan 0 0 0 0 - = - = = = r r II So [ ] [ ] [ ] [ ] m V E r E m V E r E oi or II oi II II or / 7 . 4 / 98 . 1 - = = = = 4.45 Problem 6 (4.59 on page 146) From Eq.(4.73) we see that the exponential will be in the form
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Unformatted text preview: ) ( vt x k-, provided that we factor out ti i t n k θ sin , leaving the second term as i t ti k t n ω sin , which must be t v t . Hence t i i t t v n n = λ π sin ) / 2 ( , and i i i i t v n c v sin sin = = Problem 7 (4.63 on page 146)...
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## This note was uploaded on 10/16/2011 for the course ELEC 308,315,10 taught by Professor Prof.shenghuisong during the Spring '11 term at CUHK.

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HW4 solution - vt x k provided that we factor out ti i t n...

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