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HW5a solution

# HW5a solution - Problem 1 Problem 9.9 ay s 10 4 10 3 s= =...

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Problem 1 Problem 9.9 Since m y a s a s y 05 . 2 10 8799 . 4 10 10 7 3 4 = × × = Δ = Δ - - - λ λ Problem 9.10 a m m λ θ = , since violet red , 2 , 1 θ θ = , nm a a violet violet red 390 2 1 = = λ λ λ Problem 2 Problem 9.16 s m v mv E / 10 42 . 0 2 1 6 2 × = = ; m mv h p h 9 10 73 . 1 - × = = = λ mm a s y 46 . 3 = Δ λ Problem 3 From Eq.9.36 4 ) 1 2 ( cos f t m d λ θ + = , for maximum at normal incidence and taking m=0. m n d f 6 7 0 10 2 . 9 36 . 1 4 10 5 4 4 - - × = × × = = = λ λ Problem 4 Problem9.33 o 2 . 10 10 5 2 2 5 0 = × = Δ = = Δ - rad x n x f f λ α α λ Problem 5 Newton’s ring is an equal thickness interference pattern caused by the reflection of light
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