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HW6 solution - Problem 1 Problem 10.6 = sin =(a L L b b(b L...

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Problem 1 Problem 10.6 π β ± = , θ λ θ ± = b sin (a) b L L λ θ ± ; (b) b f L λ θ 2 ± Problem 10.7 For far field, it must satisfy 02 . 0 10 619 . 4 ) 10 ( , 7 2 4 2 2 = × = > - - m m b b R λ λ , so it is far field. o 26 . 0 ) ( sin sin 1 1 1 = = = - b b λ θ λ θ so angular width is o 52 . 0 2 1 = θ Problem 2 Problem10.9 cm cm 12 87 . 36 sin ) 20 ( = × = o λ Problem 3 Problem 10.10 π α β α θ β θ α 2 , , , sin 2 , sin 2 m m mb a kb ka = = = = = N= number of fringes = m m 2 2 = = π π π α Problem 4 Since m m m m a R q 5 3 7 8 1 10 45 . 1 10 2 ) 10 328 . 6 )( 10 76 . 3 ( 22 . 1 2 22 . 1 × = × × × × = = - - λ Problem 5 m m m m a R y R y a R y m a m 46 . 0 10 0 . 3 ) 10 943 . 6 )( 0 . 2 ( sin ; sin 6 7 1 = × × = = = = = - - λ λ θ λ θ Problem 6
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