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p2f10_lec11_diffraction_photons - Physics 1200 Lecture 11...

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Physics 1200 Lecture 11 - F2010 Phasors and Interference from >2 slits Diffraction Interference pattern from a single slit Resolved images Photons and concepts in quantum theory Photon energy Photon momentum Photoelectric effect
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2 Finding interference intensity using phasors 35- ( 29 2 sin d π φ θ λ = Eq. 35-23 φ 0 E 0 E Amplitude maximum for phase difference of: 2 m φ π = φ π = Amplitude zero for phase difference of: 1 2 2 m φ π = + ÷
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3 Interference intensity for more than two slits ( 29 12 2 sin d π φ θ λ = 2 /6 φ π = 0 E 0 φ = 2 /3 φ π = φ π = 4 /3 φ π =
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Spectral, non-spectral colors, and wavelength If you take a white light beam and spread it using a prism or grating, you see something like the spectrum above. Other colors can be produced by adding one or more of the spectral colors in varying intensities. (magenta=red+blue) In the figure above the amount of blue is decreased from left to right, while the amount of red is increased. Magenta is equal parts red and blue. V I B G Y O R spectral non-spectral 400 500 550 600 700 nm
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Diffraction When waves of any type (EM, sound, water) pass through an aperture (diffraction) they: 1) spread out in angle 2) spread out more if the aperture is small 3) retain ϖ and λ As the wave emerges from the aperture, each point on the wave front acts like a point source and emits waves that are in phase. 1) Huygens’ principle 2) predict interference pattern
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Wide slit: treat each point as a source λ a Wave crest Wave trough Point of constructive interference Point of destructive interference Diffraction link
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Finding diffraction intensity minima Consider waves originating from the top of the of the slit, and from the middle of the slit. They will be out of phase when, sin 2 2 a λ θ = Furthermore, for every point in the top
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