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Unformatted text preview: Physics 1200 Lecture 11  F2010 Phasors and Interference from >2 slits Diffraction – Interference pattern from a single slit – Resolved images Photons and concepts in quantum theory – Photon energy – Photon momentum – Photoelectric effect 2 Finding interference intensity using phasors 35 ( 29 2 sin d π φ θ λ = Eq. 3523 φ E E Amplitude maximum for phase difference of: 2 m φ π = φ π = Amplitude zero for phase difference of: 1 2 2 m φ π = + ÷ 3 Interference intensity for more than two slits ( 29 12 2 sin d π φ θ λ = 2 /6 φ π = E φ = 2 /3 φ π = φ π = 4 /3 φ π = Spectral, nonspectral colors, and wavelength If you take a white light beam and spread it using a prism or grating, you see something like the spectrum above. • Other colors can be produced by adding one or more of the spectral colors in varying intensities. (magenta=red+blue) In the figure above the amount of blue is decreased from left to right, while the amount of red is increased. Magenta is equal parts red and blue. V I B G Y O R spectral nonspectral 400 500 550 600 700 nm Diffraction When waves of any type (EM, sound, water) pass through an aperture (diffraction) they: 1) spread out in angle 2) spread out more if the aperture is small 3) retain ϖ and λ As the wave emerges from the aperture, each point on the wave front acts like a point source and emits waves that are in phase. 1) Huygens’ principle 2) predict interference pattern Wide slit: treat each point as a source λ a Wave crest Wave trough Point of constructive interference Point of destructive interference Diffraction link Finding diffraction intensity minima Consider waves originating from the top of the of the slit, and from the middle of the slit. They will be out of phase when, sin 2 2 a λ θ = Furthermore, for every point in the top...
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This note was uploaded on 10/17/2011 for the course PHYS 1010 taught by Professor Schroeder during the Spring '07 term at Rensselaer Polytechnic Institute.
 Spring '07
 Schroeder
 Energy, Momentum, Photon, Diffraction

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