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p2s10_lec01_field_voltage - Physics 1200 Lecture 1 Review...

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Physics 1200 Lecture 1 Review of Electrostatics Coulomb’s Law Electric Field Electric Potential Electrostatic Potential Energy
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Coulomb’s Law 1 2 12 12 2 0 12 12 1 2 9 2 2 0 12 2 2 0 1 ˆ 4 is the force on q due to 1 9.0 10 N m /C 4 ( 8.85 10 C /N m ) πε πε ε - = 2245 × × = × × r r q q F r r F q Unlike charges attract. Like charges repel.
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Vector forces 1 12 13 14 15 The force on any particular charge is the sum of the vector forces due to all other charges that exert force on it. ... Remember you add vector forces by separating each force i = + + + + r r r r r F F F F F nto orthogonal components (e.g. - x, y, z), adding, and then recombining. It is very useful to look at the problem carefully and then choose axes to simplify calculation.
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iClicker question 1.01 +q -3q Two charges of +q and -3q are shown. For which of the lettered positions on the line could the net force on a test charge be zero? A B C D – all of them E – none of them
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The Electric Field •When E is known, the force, F , on a charge, q 0 , is given by: F = q 0 E The direction of E is the direction of the force on a positive test charge. 0 q F E r r =
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The Electric Field 0 q F E r r = For a point charge q , the force on q 0 is, Then, at q 0 ’s location, 0 2 0 1 4 qq F r πε = 2 0 0 1 4 F q E q r πε = =
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Electric Field of a Positive Point Charge The picture shows the electric field vector at several points.
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