{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# sol1 - HW#1#E1 f= v 1.2 m s = 0.5 Hz 2.4 m =#E4 a 2 = 6m =...

This preview shows page 1. Sign up to view the full content.

#E1 #E3 Hz m s m v f 5 . 0 4 . 2 / 2 . 1 = = = λ m Hz s m f v 4 . 0 5 / 0 . 2 = = = λ HW #1 #E4 a) b) #E6 a) mass per unit of length = b) m m 3 6 2 = = λ λ s m Hz m f v / 6 2 3 = × = × = λ m kg m kg / 15 . 0 8 . 0 12 . 0 = s m N F v / 30 135 = = = #E11 a) b) m kg / 15 . 0 μ 0.5m Hz m s m v f 170 2 / 340 = = = λ #SP1 a) mass per unit of length = b) c) m m L 2 5 . 0 4 = = = λ λ s m N F v / 10 30 m kg m kg / 3 . 0 8 4 . 2 = s m v 4 / 10 λ b) d) e) #SP2 ) it f l th m kg / 3 . 0 = = = μ m Hz f 5 . 2 = = = cycles x m m x L x 2 8 4 = = × = × λ s s m m 8 . 0 / 10 8 = k kg / 032 0 04 . 0 #SP2 a)mass per unit of length = b) c) d) m kg m . 25 . 1 = s m m kg N F v / 150 / 032 . 0 720 = = = μ m cm cm L 28 . 1 128 64 2 1 1 = = = = λ λ Hz m s m v f 2 . 117 28 . 1 / 150 1 = = = λ
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online