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Unformatted text preview: HW #1
#E1 f= λ
v 1 .2 m / s
= 0.5 Hz
2 .4 m = #E4 a) 2λ = 6m
∴ λ = 3m b) #E3 λ = v = λ × f = 3m × 2 Hz = 6m / s #E6 a) mass per unit of length =
F b) v = 0.12kg
= 0.15kg / m
0 .8 m 135 N
= 30m / s
0.15kg / m = μ v 2.0m / s
=
= 0.4m
f
5 Hz #E11 a) b) f = λ
v 340m / s
= 170 Hz
2m = 0.5m λ = L = 0.5m
4
∴ λ = 2m
#SP1 a) mass per unit of length = F b) v =
d) μ 2.4kg
= 0.3kg / m
8m 30 N
= 10m / s
0.3kg / m = x×λ = L c)
c) λ= e) v 10m / s
=
= 4m
f
2.5 Hz 8m
= 0 .8 s
10m / s x × 4 m = 8m
∴ x = 2cycles #SP2 a)mass per unit of length = F b) v = μ d) f1 = e) 2× v λ1 λ2 720 N
= 150m / s
0.032kg / m = = 0.04kg
= 0.032k / m
kg
1.25m c) λ1
2 = L = 64cm λ1 = 128cm = 1.28m 150m / s
= 117.2 Hz
1.28m =L 2
λ 2 = L = 0.64cm f2 = v λ2 = 150m / s
= 234.4 Hz
0.64m or 2 f1 = f 2
2 × 117.2 Hz = 234.4 Hz ...
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This note was uploaded on 10/20/2011 for the course PHY 309L taught by Professor Sai during the Spring '08 term at University of Texas at Austin.
 Spring '08
 SAI
 Physics, Mass

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