sol1 - HW #1 #E1 f= λ v 1 .2 m / s = 0.5 Hz 2 .4 m = #E4...

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Unformatted text preview: HW #1 #E1 f= λ v 1 .2 m / s = 0.5 Hz 2 .4 m = #E4 a) 2λ = 6m ∴ λ = 3m b) #E3 λ = v = λ × f = 3m × 2 Hz = 6m / s #E6 a) mass per unit of length = F b) v = 0.12kg = 0.15kg / m 0 .8 m 135 N = 30m / s 0.15kg / m = μ v 2.0m / s = = 0.4m f 5 Hz #E11 a) b) f = λ v 340m / s = 170 Hz 2m = 0.5m λ = L = 0.5m 4 ∴ λ = 2m #SP1 a) mass per unit of length = F b) v = d) μ 2.4kg = 0.3kg / m 8m 30 N = 10m / s 0.3kg / m = x×λ = L c) c) λ= e) v 10m / s = = 4m f 2.5 Hz 8m = 0 .8 s 10m / s x × 4 m = 8m ∴ x = 2cycles #SP2 a)mass per unit of length = F b) v = μ d) f1 = e) 2× v λ1 λ2 720 N = 150m / s 0.032kg / m = = 0.04kg = 0.032k / m kg 1.25m c) λ1 2 = L = 64cm λ1 = 128cm = 1.28m 150m / s = 117.2 Hz 1.28m =L 2 λ 2 = L = 0.64cm f2 = v λ2 = 150m / s = 234.4 Hz 0.64m or 2 f1 = f 2 2 × 117.2 Hz = 234.4 Hz ...
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This note was uploaded on 10/20/2011 for the course PHY 309L taught by Professor Sai during the Spring '08 term at University of Texas at Austin.

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