# sol4 - 6 Ω resistor -> the total current splits up the...

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#E2 #E3 #E5 #E9 (a) (b) In a series circuit, current has only one path. So, the current is the same through each resistor. (c) #E12 (a) (b) (c) voltage difference across each resistance is the same #E16 (a) (b) #SP1 (a) parallel circuit resistance, (b) (c) (d) C s s C A t I q 150 min 1 60 min 1 ) / ( 5 . 2 A V R V I IR V 25 . 0 24 6 , 200 6 . 0 120 , A V I V R IR V A V R V I 1 . 0 60 0 . 6 60 25) 20 (15 resistance Total V A IR V 2 20 1 . 0 , 8 , 8 1 24 1 24 1 24 1 1 Total Total R R A V R V I IR V 5 . 1 8 12 , A V R V I 5 . 0 24 12 W A V I P 770 7 110 7 . 15 ) 7 ( 770 2 2 A W I W R 12 Ω 6 Ω 8 Ω 4 , 4 1 12 1 6 1 1 Total parallel R R A V R V I 125 . 0 12 5 . 1 2 8 1 ) (4 resistance Total V 1 V 2 A V R V I V V V V V V V V V A IR V Total 083 . 0 6 5 . 0 5 . 0 5 . 1 1 1 8 125 . 0 2 2 2 2 2 1 1 W A R I P 125 . 0 8 ) 125 . 0 ( 2 2 HW4

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(e) the current flowing through the 8 Ω resistor is greater than that flowing through the
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Unformatted text preview: 6 Ω resistor -> the total current splits up the branch. #SP5 (a) (b) current limit -> 15A too large a current could cause the wires to overheat. So, the fuse will blow. And, the entire current is disrupted, and no current will flow to any of the attached appliances. (c) , 35 . 4 115 500 , 44 . 10 115 1200 , 22 . 5 115 600 A V W P I A V W P I A V W P I 11 1200 ) 115 ( 2 2 W V P R R R I P 2...
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## This note was uploaded on 10/20/2011 for the course PHY 309L taught by Professor Sai during the Spring '08 term at University of Texas.

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sol4 - 6 Ω resistor -> the total current splits up the...

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