HW_6-QualityControl

HW_6-QualityControl - a. (1.5 Points) CL = 53/12 = 4.42 UCL...

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Problem 6: a. Control limits for X-bar chart : (1.5 points) CL = 12.00 UCL = 12.00 + (0.48)(0.60) = 12.29 LCL = 12.00 – (0.48)(0.60) = 11.71 X-bar Chart 11 11.2 11.4 11.6 11.8 12 12.2 12.4 1 2 3 4 5 Sample Number Process mean is not in control Control Limits for R-chart: (1.5 points) CL = 0.60 UCL = (2.0)(0.60) = 1.20 LCL = (0)(0.6) = 0 R-Chart 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1 2 3 4 5 Sample Number R-Chart is in control, but since X-bar chart is not in control, then the process is not in control (0.5 point).
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Problem 8: a. 1.5 points CL = p = 200 18 = 0.09 σ p = 20 ) 91 . 0 )( 09 . 0 ( = 0.064 UCL = 0.09 + 3(0.064) = 0.282 LCL = 0.09 – 3(0.064) = - 0.102 = 0 b. P-Chart 0 0.05 0.1 0.15 0.2 0.25 0.3 0.35 1 2 3 4 Sample Number Process is out of control because the first sample is above the upper control limit (0.5 point) Problem 10:
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Unformatted text preview: a. (1.5 Points) CL = 53/12 = 4.42 UCL = 4.42 + 3* 42 . 4 = 10.73 LCL = 4.42 - 3* 42 . 4 = = -1.89 = 0 b. Since all the samples are within the range between the UCL and LCL, the process is in control (0.5 point) Problem 12: C pk = min( 3-USL , 3 LSL-) = min( ) 5 ( 3 80 100-, ) 5 ( 3 70 80-) = min( 15 20 , 15 10 ) = 0.67 (1 point) C p = 6 LSL USL-= ) 5 ( 6 70 100-= 1 (1 point) Looking at the C P index by itself would lead us to believe that the machine is capable (0.5 point). This process is not capable since the C pk value is less than 1. Since Cpk is more powerful than Cp, our final answer is that the process is not capable. (0.5 point)...
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This note was uploaded on 10/17/2011 for the course MNGT 368 taught by Professor Curthurds during the Spring '08 term at Nicholls State.

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HW_6-QualityControl - a. (1.5 Points) CL = 53/12 = 4.42 UCL...

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