µoil 2.5 cP µwater 0.8 cP ρoil 0.85 gm/cm3 ρwater 1 gm/cm3 q 5 cm3/min Q is directly proportional to density of fluid used and inversely proportional to the viscosity Since everything else in the Darcy equation for both the experiments is the same Qoil 1.36 cm3/min Converted Units Darcy Units L 1.9 in 0.04826 m 4.826 cm d 1.5 in 0.0381 m3/sec 3.81 cm 46.05 psi 317503.57 N/m2 3.1326530612 psi Q 0.05 mL/min 8.33333E-010 m3/sec 0.0008333333 cc/s µ 0.443 cP 0.000443 Nsec/m2 0.443 cP k=Q*mu*L/(A*delP) k 4.92113E-017 m2 4.99089E-005 D 4.98645E-005 D k 0.049864549 mD L1 50 ft L2 15 ft L3 85 ft k1 100 mD k2 200 mD k3 300 mD kavg 174.7572816 mD h1 5 ft h2 7 ft h3 15 ft k1 50 mD k2 110 mD k3 795 mD kvg 479.4444444 mD 1 . In an experiment similar to that of Darcy’s, the flow rate of water was observed to be 5.0cm3/min. If the experiment were to be repeated with oil, what would be the flow rate for oil? The difference between the upstream and downstream hydraulic gradients Δh are the same for both the experiments (measured with
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This note was uploaded on 10/18/2011 for the course ECON 101 taught by Professor Erre during the Spring '11 term at Angelo State.