LAB REPORT FOR MP6 EXPERIMENT - Now d using equation d = 0.0038227521 x 6328 x 10e-08 d=2.41e-07 angstroms VII 1 =1.38Å = d 3 56 Å L = 10cm Calculate

LAB REPORT FOR MP6 EXPERIMENT: Diffraction of Light VI(1) Set L=200cm and used the square array with width d=0.1mm m x m y ℓ (cm) -1 2 3 2.23 0.859 0.085 0 2 2.5 2 0.716 0.076 1 2 3 2.23 0.859 0.085 -2 1 2.8 2.23 0.802 0.085 -1 1 1.9 1.41 0.544 0.053 0 1 1.5 1 0.429 0.038 1 1 1.9 1.41 0.544 0.053 2 1 2.8 2.23 0.802 0.085 -2 0 2.5 2 0.716 0.076 -1 0 1.9 1 0.544 0.038 0 0 0 0 0 0 1 0 1.9 1 0.544 0.038 2 0 2.5 2 0.716 0.076 -2 -1 3 2.23 0.859 0.085 -1 -1 1.9 1.41 0.544 0.053 0 -1 1.5 1 0.429 0.038 1 -1 1.9 1.41 0.544 0.053 2 -1 2.9 2.23 0.830 0.085 -1 -2 3 2.23 0.859 0.085 0 -2 2.8 2 0.802 0.076 1 -2 3 2.23 0.859 0.085 VI(2)

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Vs Slope = 0.038227521 Uncertainity in slope = 9.99996E-05

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Unformatted text preview: Now d using equation, d = 0.0038227521 x 6328 x 10e-08 d=2.41e-07 angstroms VII 1. ? =1.38Å = . d 3 56 Å L = 10cm Calculate angle θ for point (1,0). And calculate ℓ on the film. We can calculate θ using equation d = ? Now, here m x =1 and m y =0 So using equation = 1 Therefore, =22.80 o Also, Thus, ℓ = L Therefore, ℓ = 4.20cm...
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