5_Chapter 20 HomeworkCH20 Induced Voltages and Inductance

# 5_Chapter 20 HomeworkCH20 Induced Voltages and Inductance -...

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Induced Voltages and Inductance 179 Problem Solutions 20.1 The magnetic flux through the area enclosed by the loop is ( ) () ( ) 2 22 cos cos0 0.30 T 0.25 m 5.9 10 T m B BA B r θπ π  Φ= = °= = ×  2 20.2 The magnetic flux through the loop is given by cos B BA θ Φ = where B is the magnitude of the magnetic field, A is the area enclosed by the loop, and is the angle the magnetic field makes with the normal to the plane of the loop. Thus, 52 7 2 10 cos 5.00 10 T 20.0 cm 1.00 10 T m cos B BA 2 -2 m cos 1 cm θθ −− = × ×     = (a) When B is perpendicular to the plane of the loop, JG 0 = ° and 72 10 T m B × 1.00 (b) If 8 30.0 , then 1.00 10 T m cos30.0 8.66 10 T m B Φ = × ° 2 (c) If ( ) 90.0 , then 1.00 10 T m cos90.0 0 B Φ ° = 20.3 The magnetic flux through the loop is given by cos B BA Φ = where B is the magnitude of the magnetic field, A is the area enclosed by the loop, and is the angle the magnetic
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## This document was uploaded on 10/20/2011.

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