Optical Instruments341Problem Solutions 25.1Using the thin lens equation, the image distance is ( )( )150 cm25.0 cm30.0 cm150 cm25.0 cmpfqpf===−−so the image is located 30.0 cm beyond the lens . The lateral magnification is 30.0 cm1150 cm5qMp=−= −25.2The f-number of a camera lens is defined as -numberfocal length diameterf=. Therefore, the diameter is 55 mm31 mm-number1.8fDf=25.3The thin lens equation, 111pqf+=, gives the image distance as ( )( )3100 m52.0 mm52.0 mm100 m52.010mpfq−=×From the magnitude of the lateral magnification, M hhqp′−, where the height of
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