146CHAPTER 19 19.5Gravitational force: ( )( )3129.1110kg9.80 m sgFmg−== ×(=308.9310N downward−×Electric force: )( )191.6010C100 N CeFqE−==− ×−=(171.6010N upward−×Magnetic force: )( )( )()191717sin1.6010C6.0014.8010N in direction opposite4.8010N downwardmmvBFθ−−−×=×660 m s50.010T sinright hand rule predicti−−××90.0on°19.6From sinvB=(, the magnitude of the force is found to be )( )( )191.6010C66176.210 m s50.010T sin 90.04.9610NF××°v−Using the right-hand-rule (fingers point westward in direction of JGB, so they move downward toward the direction of as you close the hand, the thumb points southward. Thus, the direction of the force exerted on a proton (a positive charge) is
This is the end of the preview. Sign up
access the rest of the document.