6_Chapter 24 HomeworkCH24 Wave Optics

# 6_Chapter 24 HomeworkCH24 Wave Optics - 308 CHAPTER 24...

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308 CHAPTER 24 Problem Solutions 24.1 ( ) ( ) ( ) 1 9 2 3 1 632.8 10 m 5.00 m 1.58 10 m 1.58 cm 0.200 10 m bright m m L L L y y y m m d d d λ λ λ + = = + = × = = × × = 24.2 (a) For a bright fringe of order m , the path difference is m δ λ = , where At the location of the third order bright fringe, 0, 1, 2, m = 3 m = and ( ) 3 3 3 589 nm 1.77 10 nm 1.77 δ λ = = = × = m µ (b) For a dark fringe, the path difference is 1 2 m δ λ = + , where At the third dark fringe, 0,1,2, m = 2 m = and ( ) 3 1 5 2 589 1.47 10 nm 1.47 m 2 2 δ λ = + = = × = nm µ 24.3 (a) The distance between the central maximum and the first order bright fringe is 1 0 bright bright m m L y y y d λ = = = = , or ( ) ( ) 9 3 3 546.1 10 m 1.20 m 2.62 10 m 2.62 mm 0.250 10
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