8_Chapter 22 HomeworkCH22 Reflection and Refraction of Light

8_Chapter 22 HomeworkCH22 Reflection and Refraction of...

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Unformatted text preview: 240 CHAPTER 22 22.6 Mirror 2 Light beam Mirror 2 50° 40.0° i2 = 50° 40° P 1.25 m d 40° Mirror 1 i1 = 40° 50° 50° Mirror 1 1.25 m (a) From geometry, 1.25 m = d sin 40.0° , so d = 1.94 m (b) 22.7 50.0° above horizontal , or parallel to the incident ray n1 sin θ1 = n2 sin θ 2 q1 n1 = 1.00 sin θ1 = 1.333 sin 45.0° q2 sin θ1 = (1.333)(0.707 ) = 0.943 n2 = 1.333 θ1 = 70.5° → 22.8 19.5° above the horizontal c The speed of light in water is vwater = , and in Lucite vLucite = ® nwater time required to transverse the double layer is ∆t1 = c nLucite . Thus, the total dwater dLucite dwater nwater + dLucite nLucite + = vwater vLucite c The time to travel the same distance in air is ∆t2 = dwater + dLucite , so the additional time c required for the double layer is ∆t = ∆t1 − ∆t2 = = (1.00 × 10 −2 dwater ( nwater − 1) + dLucite ( nLucite − 1) c m ) ( 1.333 − 1) + ( 0.500 × 10 −2 m ) ( 1.59 − 1) 3.00 × 10 m s 8 = 2 .09 × 10 −11 s ...
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This document was uploaded on 10/20/2011.

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