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9_Chapter 16 HomeworkCH16 Electrical Energy and Capacitance

9_Chapter 16 HomeworkCH16 Electrical Energy and Capacitance...

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Electrical Energy and Capacitance 43 16.9 (a) Use conservation of energy ( ) ( ) s e s e f i KE PE PE KE PE PE + + = + + ( or ) ( ) ( ) 0 s e KE PE PE + ∆ + ∆ = ( ) 0 KE = ( ) since the block is at rest at both beginning and end. 2 max 1 0 2 s PE kx = max x ( ) ( , where is the maximum stretch of the spring. ) max e PE W QE x = − = − Thus, ( ) 2 max max 1 2 kx QE x + = 0 0 , giving ( ) ( ) 6 5 5.00 10 V m 0.500 m N m × × = max 2 50.0 10 C 2 100 QE x k = = (b) At equilibrium, Σ = Therefore, 0, or 0 s e eq F F F kx QE + = + = 1 0.250 m 2 eq max QE x x k = = = Note that when the block is released from rest, it overshoots the equilibrium
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