9_Chapter 17 HomeworkCH17 Current and Resistance

9_Chapter 17 HomeworkCH17 Current and Resistance - Current...

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Current and Resistance 77 (a) From L R A ρ = , we find that () 8 8 1.70 10 m 3.40 10 m 0.500 A LL R  ×Ω ==    ( L Inserting this expression for A into equation (1) gives ) 82 7 3 3.40 10 m 1.12 10 m L −− ×= × , which yields 1.82 m L = (b) From equation (1), 27 1.12 10 m 4 d A L π × 3 , or 73 4 4 1.12 10 m 4 1.12 10 m 1.82 m 2.80 10 m 0.280 mm d L ππ ×× = 17.13 From L R A = , we obtain 2 4 dL A R , or ( ) 4 4 5.6 10 m 2.0 10 m 4 1.7 10 m 0.17 mm 0.050 L d R × = 17.14 ( )( ) 8 2 2 3 41 .7 10 m 15
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This document was uploaded on 10/20/2011.

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