This preview shows page 1. Sign up to view the full content.
Mirrors and Lenses
275
23.11
The
magnified
,
virtual
images formed by a concave mirror are upright, so
0
M
>
.
Thus,
5.00 cm
2.50
2.00 cm
q
h
M
ph
′
=−
=
=
=+
(
, giving
)
2.50
2.50
3.00 cm
qp
+
7.50 cm
The mirror equation then gives,
1211
1
1
3.00 cm
7.50 cm
7.50 c
fRpq
1
m
−
==+=
−
=
or
7.50 cm
1.50
f
==
5.00 cm
23.12
Realize that the magnitude of the radius of curvature,
R
, is the same for both sides of
the hubcap. For the convex side,
RR
= −
; and for the concave side,
. The object
distance
p
is positive (real object) and has the same value in both cases. Also, we write
the virtual image distance as
qq
= −
in each case. The mirror equation then gives:
This is the end of the preview. Sign up
to
access the rest of the document.
This document was uploaded on 10/20/2011.
 Spring '09
 Physics, Work

Click to edit the document details