Mirrors and Lenses27723.15The focal length of the mirror may be found from the given object and image distances as 111fp=+q, or ( )( )152 cm18.0 cm16.1 cm152 cm18.0 cmpqf===+++For an upright image twice the size of the object, the magnification is 2.00qMp=−2.00qpgiving Then, using the mirror equation again, pqf+=becomes 122.01 10ppp f−+=−==or 16.1 cmfp8.05 cm=23.16A convex mirror ( )0R<produces upright, virtual images of real objects. Thus, 0M>giving 13qpM, or 3pq
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