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Mirrors and Lenses
277
23.15
The focal length of the mirror may be found from the given object and image distances
as
111
fp
=+
q
, or
( )( )
152 cm
18.0 cm
16.1 cm
152 cm
18.0 cm
pq
f
==
=
+
++
For an upright image twice the size of the object, the magnification is
2.00
q
M
p
=−
2.00
qp
giving
Then, using the mirror equation again,
p
qf
+
=
becomes
1
2
2.0
1 1
0
p
p
p f
−
+=−
=
=
or
16.1 cm
f
p
8.05 cm
=
23.16
A convex mirror
( )
0
R
<
produces upright, virtual images of real objects.
Thus,
0
M
>
giving
1
3
q
p
M
, or
3
p
q
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This document was uploaded on 10/20/2011.
 Spring '09
 Physics, Work

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